The maximum value of sin x cos xsinxcosx is
Splet22. avg. 2024 · The question in my textbook was to find the minimum value of function, which was pretty simple, $0$. But that led me to thinking if we could find it's range. I tried … SpletMaximum value of f(x)= sinx+cosx is A 1 B 2 C 1 √2 D √2 Solution The correct option is D √2 y =f(x) =sinx+cosx dy dx =cosx−sinx For dy dx =0,sinx =cosx, tanx =1 ∴ x= 45∘ y …
The maximum value of sin x cos xsinxcosx is
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Splet22. mar. 2024 · The maximum value of sin x . cos x is (A) 1/4 (B) 1/2 (C) √2 (D) 2 √2 This question is similar to Ex 6.5, 9 - Chapter 6 Class 12 - Application of Derivatives This video … SpletAt x=sin −1 61 we get. f"(x)<0. Hence. f(x=sin −1 61) = 61− 6 62. = 3 63−1. = 3 62. This is the maximum value. for minimum value f"(x)>0 at x=cos −1(0)
Splet13. mar. 2024 · 具体来说,我们可以考虑比较函数f(x) = cos(x)/x和一个已知的发散的函数g(x) = 1/x,当x趋近于无穷大时,两个函数的极限都等于零,即: lim x->∞ f(x)/g(x) = lim x->∞ x*cos(x) = ∞ 因此,根据极限比较测试法,如果一个函数在某一点x0处与一个发散的函数g(x)的比值趋近于 ... SpletUntitled - Free download as PDF File (.pdf) or read online for free.
SpletAnswer (1 of 4): f(x) = \sin (\cos x) Equating f'(x) to 0 \displaystyle \frac{d}{dx} f(x) = -\sin x (\cos(\cos x) = 0 \sin x = 0 or \cos(\cos x) = 0 \implies x=0 or ... Splet12. mar. 2024 · Solution For d the maximum \& minimum value of: 2+3sinx+4cosx (ii) 3+sin2x+cos2x ii) 4sinxsin(60∘−x)sin(60∘+x) (iv) sin2(120 ... 4sinxsin(60∘−x)sin(60∘+x) (iv) sin2(120∘+x)+sin2(120∘− D) The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask ...
Splet22. nov. 2015 · Clearly $\sin x$ and $\cos x$ are differentiable functions, hence their difference $(\sin x - \cos x)$ is also differentiable. So we can differentiate $\sin x - \cos …
SpletOldja meg matematikai problémáit ingyenes Math Solver alkalmazásunkkal, amely részletes megoldást is ad, lépésről lépésre. A Math Solver támogatja az alapszintű matematika, algebra, trigonometria, számtan és más feladatokat. molly\\u0027s nailsi-15 accident near barstowSplet08. apr. 2024 · d x d j (x) = (sin x sin x) = (sin x) ′ sin x + sin x (sin x) ′ = (cos x) sin x + sin x (cos x) = 2 sin x cos x = sin 2 x ग्रश्नावली 13.2 1. x = 10 पर x 2 − 2 का अवकलज ज्ञात कीजिए। 2. x = 1 पर x का अवकलज ज्ञात कीजिए। 3. molly\\u0027s nails columbia ilSpletFind the area of the region enclosed by the graphs of y = 3 sin (x) and y= 5πT 2 cos (x) from x = : 0 to x = 6. BUY. Calculus: Early Transcendentals. i14 phone best buySplet(x − a)n + 1, where M is the maximum value of f (n + 1)(z) on the interval between a and the indicated point, yields Rn ≤ 1 1,000 on the indicated interval. f(x) = sin(x) on [−𝜋, 𝜋], a = 0. Find the smallest value of n such that the remainder estimate Rn ≤ M (n + 1)! (x − a)n + 1, where M is the maximum value of f (n + 1 ... i15 auctions websiteSpletOldja meg matematikai problémáit ingyenes Math Solver alkalmazásunkkal, amely részletes megoldást is ad, lépésről lépésre. A Math Solver támogatja az alapszintű … molly\u0027s mutts animal rescueSplet19. sep. 2024 · Therefore at x = π/4, f (x) is maximum and π/4 is the point of maxima. Now we will find the maximum value of sin x cos x by substituting x = π/4, in f (x), we get. f … i14 phone cover